1
S3=a1(1-q^3)/(1-q),S2=a1(1-q^2)/(1-q)
故:a1(1-q^3)/(1-q)=-3*a1(1-q^2)/(1-q)
即:1+q+q^2=-3-3q,即:q^2+4q+4=(q+2)^2=0,故:q=-2
2
|2a-b|^2=(2a-b)·(2a-b)=4|a|^2+|b|^2-4a·b=4+|b|^2-4a·b
=4+|b|^2-4|b|cos(π/4)=4+|b|^2-2sqrt(2)|b|=10
故:|b|^2-2sqrt(2)|b|-6=0,故:|b|=(2sqrt(2)±4sqrt(2))/2
即:|b|=3sqrt(2)或-sqrt(2)(不和题意,舍去)
即:|b|=3sqrt(2)