x/(x+1)+1=(2x+2)/x
x/(x+1)+1=2(x+1)/x
令x/(x+1)=z
z+1=2/z
z^+z-2=0
(z-1)(z+2)=0
z=1 z=-2
x/(x+1)=1
x=x+1
方程无解
x/(x+1)=-2
x=-2x-2
3x=-2
x=-2/3
x/(x+1)+1=(2x+2)/x
x/(x+1)+1=2(x+1)/x
令x/(x+1)=z
z+1=2/z
z^+z-2=0
(z-1)(z+2)=0
z=1 z=-2
x/(x+1)=1
x=x+1
方程无解
x/(x+1)=-2
x=-2x-2
3x=-2
x=-2/3