..sin^2（π+α）*cos（π+α）*cos

..sin^2（π+α）*cos（π+α）*cos（-α-2π）/tan（π+α）*sin^3（π/2+α）*sin（-

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原式=（-sina）*（-sina）*（-cosa）*（-cosa）/（-tana）*sina*sina*sina*（-sina）=cosa*cosa/tana*sina=tana*sina

化简：（Ⅰ）sin(α−2π)cos(α+π)tan(α−99π)cos(π−α)sin(3π−α)sin(−α−π)；
sin(π/2+α)·cos(π/2-α)/cos(π+α)+sin（π-α）·cos（π/2+α）/sin（π+α）=
tan(π-α)*sin^2(α+π/2)*cos(2π-α)/cos^3(-α-π)*tan(2π-α) sin^2就
tan(3π-α)/sin(π-α)sin(3/2π-α)+sin(2π-α)cos(α-7/2π)/sin(3/2π+
设tan（π+α）=2，则sin(α−π)+cos(π−α)sin(π+α)−cos(π+α)=（　　）
已知tanα=2,sinα+cosα＜0,求[sin(2π-α)*sin(π+α)*cos(-π+α)]/[sin(3π
化简：sin(3π+α)•cos(π−α)•tan(3π2+α)cos(π3)•sin(π2−α)•cos(−α)=__
化简（1）tan(π−α)cos(2π−α)sin(−α+3π2)cos(−α−π)sin(−π−α)．
化简：tan(π+α)cos(2π+α)sin(α−3π2)cos(−α−3π)sin(−3π−α)=______．
已知f（α）=sin2(π−α)•cos(2π−α)•tan(−π+α)sin(−π+α)•tan(−α+3π)．