Pn(Xn,Yn)是函数y=x²(x≥0)图像上的动点,以Pn为圆心的⊙Pn与X轴都相切,且⊙Pn与⊙Pn+1

1个回答

  • 1 P1,P2坐标分别是(x1,x1^2)(x2,x2^2) R1=x1^2,R2=x2^2

    ---

    由于圆1和圆2相切,根据勾股定理

    (P1P2)^2=(R1+R2)^2=(y1-y2)^2+(x1-x2)^2

    (x1^2+x2^2)^2=(x1^2-x2^2)^2+(x1-x2)^2

    (x1-x2)^2=4x1^2x2^2 x1-x2=2x1x2

    ---

    所以(1/x2)-(1/x1)=(x1-x2)/x1x2 =2

    同理(1/x3)-(1/x2)=(x2-x3)/x2x3 =2 ...

    所以 1/x1 ,1/x2 ,1/x3 ...成等差数列

    由于 x1=1 所以x2=1/3 x3=1/5 x4=1/7

    ---

    ---

    2 S1=πx1^4 S2=πx2^4 ...

    约去√π 证明x1^2+x2^2+x3^2+.< 3/2 即可

    ---

    x1^2+x2^2+x3^2+.

    =1+1/3^2 +1/5^2 +1/7^2 +...

    ---

    因为1+1/2^2 +1/3^2 +1/4^2 +1/5^2 +.

    =(1+1/3^2 +1/5^2 +1/7^2+...)+(1/4)(1+1/2^2 +1/3^2 +1/4^2 +1/5^2...)

    就是 1+1/3^2 +1/5^2 +1/7^2+...=(3/4)(1+1/2^2 +1/3^2 +1/4^2 +1/5^2...)

    ---

    又因为 1+(1/2^2 +1/3^2)+(1/4^2 +1/5^2 +1/6^2 +1/7^2)+1/8^2 +...