/x-1/+/y+2/+/z-3/=0,
/x-1/=0
x=1
/y+2/=0
y=-2
/z-3/=0,
z=3
(x+1)(y-2)(z-3)
=(1+1)(-2-2)(3-3)
=2*(-4)*0
=0
若/x-1/+/y+2/+/z-3/=0,则(x+1)(y-2)(z-3)的值为多少
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