Question

会计考试,直线回归方程.X:1.2 2 3 3.5 4 5 .Y:10 12 15 17 19 22 求Y倚X直线回归方

Answer 1

x=2:6;

y=[2.2,3.8,5.5,6.5,7.0];

A=polyfit(x,y,1);

a=A(1)

b=A(2)

plot(x,y,'r*');hold on;

plot(x,a*x+b);hold off;%y=ax+b

a =

1.2300

b =

0.0800