设Y1=aX² Y2=b/(X+3)
X=0时,Y1=0 Y2=b/3则
Y=Y1+Y2=b/3=2 ①
X=1时Y1=a Y2=b/4则
Y1+Y2=a+b/4=0 ②
由①得
b=6
代入②
a=-3/2
所以Y1=-(3/2)X² Y2=6/(X+3)
Y=Y1+Y2=-(3/2)X²+6/(X+3)
设Y1=aX² Y2=b/(X+3)
X=0时,Y1=0 Y2=b/3则
Y=Y1+Y2=b/3=2 ①
X=1时Y1=a Y2=b/4则
Y1+Y2=a+b/4=0 ②
由①得
b=6
代入②
a=-3/2
所以Y1=-(3/2)X² Y2=6/(X+3)
Y=Y1+Y2=-(3/2)X²+6/(X+3)