Question

关于整式的乘除的问题因式分解4x²y²-(x²+y²)²

Answer 1

4x²y²-(x²+y²)²

=(2xy)²-(x²+y²)²

=[2xy+(x²+y²)][2xy-(x²+y²)]

=-(x²+2xy+y²)(x²-2xy+y²)

=-(x+y)²(x-y)²