弦长2.5米,拱高0.2米,请问弧长是多少?

1个回答

  • 弦长L=2.5米, 拱高H=0.2米, 请问弧长C是多少?

    弧半径为R,弧所对的圆心角为A.

    R^2=(R-H)^2+(L/2)^2

    R^2=R^2-2*R*H+H^2+L^2/4

    2*R*H=H^2+L^2/4

    R=H/2+L^2/(8*H)

    =0.2/2+2.5^2/(8*0.2)

    =4.00625米

    A=2*ARC SIN((L/2)/R)

    =2*ARC SIN((2.5/2)/4.00625)

    =36.36度

    =36.36*PI/180

    =0.634621弧度

    C=R*A=4.00625*0.634621=2.542米