sin-3π/4= cos11π/6= tan13π/4= sin7π/2= cos-3π/2= sin10π/3=
1个回答
sin-3π/4=-√2/2
cos11π/6=-√3/3
tan13π/4=1
sin7π/2=-1
cos-3π/2=0
sin10π/3=-√3/2
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sin2π/3=?;cos2π/3=?;sin7π/6=?;cos7π/6=?说下