1. m的值=4g/16% - 4g = 21g
2.设HClz质量为x
HCl + NaOH == NaCl + H2O
36.5 40
x 4g
36.5/x=40/4g
x=3.65g
稀盐酸溶质质量分数=100%×3.65g/50g=7.3%
记得采纳我~~
1. m的值=4g/16% - 4g = 21g
2.设HClz质量为x
HCl + NaOH == NaCl + H2O
36.5 40
x 4g
36.5/x=40/4g
x=3.65g
稀盐酸溶质质量分数=100%×3.65g/50g=7.3%
记得采纳我~~