1.左边>=a*2bc+b*2ac=2abc+2abc=4abc
2.即√6+√7>√8+√5
即√6-√5>√8-√7
即(6-5)/(√6+√5)>(8-7)/(√8+√7)
即1/(√6+√5)>1/(√8+√7)
即√8+√7>√6+√5,显然成立
1.左边>=a*2bc+b*2ac=2abc+2abc=4abc
2.即√6+√7>√8+√5
即√6-√5>√8-√7
即(6-5)/(√6+√5)>(8-7)/(√8+√7)
即1/(√6+√5)>1/(√8+√7)
即√8+√7>√6+√5,显然成立