Question

求解3道平方差题一.（a+1)(a-1)(a的2次方+1）（a的四次方+1）（a的八次方+1）二.（X+2y-3）（X-

Answer 1

=(a^2-1)(a^2+1)(a^4+1)(a^8+1)=a^16-1

=[x-(3-2y)][x+(3-2y)]=x^2-(3-2y)^2=x^2-4*(y^2)+12y-9

=y^2-4-(y^2+4y-5)=1-4y