已知x+y=2,xy=-5求
(1)1/x+1/y的值
=(x+y)/(xy)
=2/(-5)
=-2/5;
(2)求1/x²+1/y²的值
=(x²+y²)/(x²y²)
=[(x+y)²-2xy]/(x²y²)
=[2²+10]/25
=14/25;
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已知x+y=2,xy=-5求
(1)1/x+1/y的值
=(x+y)/(xy)
=2/(-5)
=-2/5;
(2)求1/x²+1/y²的值
=(x²+y²)/(x²y²)
=[(x+y)²-2xy]/(x²y²)
=[2²+10]/25
=14/25;
很高兴为您解答,skyhunter002为您答疑解惑
如果本题有什么不明白可以追问,