解第一题
原式=(-5)³×(-3/5)-32÷(-2)²×(-1又1/4)
=(-125)×(-3/5)-32÷4×(-5/4)
=125×3/5-8×(-5/4)
=75-(-10)
=75+10
=85
解第二题
原式=[-9×(-1/3)²-0.8]÷(-5又2/5)
=(-9×1/9-0.8)÷(-27/5)
=(-1-0.8)×(-5/27)
=(-1.8)×(-5/27)
=1.8×5/27
=9/5×5/27
=1/3
解第三题
原式=5又3/5÷(-5)²×(-5/14)+|-0.2|
=(28/5)÷25×(-5/14)+0.2
=28/5×1/25×(-5/14)+1/5
=-(28/5×1/25×5/14)+1/5
=-2/25+1/5
=-2/25+5/25
=5/25-2/25
=3/25
解第四题
原式=-3³-[-5-0.2÷(4/5)×(-2)²]
=-27-[-5-0.2÷(4/5)×4]
=-27-(-5-1/5×5/4×4)
=-27-(-5-1)
=-27-(-6)
=-27+6
=-(27-6)
=-21
解第六题
原式=56÷(-12+8)+(-2)×5
=56÷(-4)+(-10)
=(-14)+(-10)
= -24
解第七题
原式=25-3×[-3²+(-2)×(-3)]+(-5)²
=25-3×(-9+6)+25
=25-3×(-3)+25
=25+9+25
=59