Question

f(x)=(1-sinx)/x求导数要详解!

Answer 1

分式求导公式 [f(x)/g(x)]'= [f'(x)*g(x)- f(x)g'(x)]/ g(x)^2

= [-cosx * x - (1-sinx) * 1]/ x^2

= ( - xcosx + sinx -1)/ x^2