∠AHE与∠CHG相等证明:∵AD平分∠BAC∴∠BAD=∠BAC/2∵BE平分∠ABC∴∠ABE=∠ABC/2∴∠AHE=∠BAD+∠ABE=(∠BAC+∠ABC)/2=(180-∠ACB)/2=90-∠ACB/2∵CF平分∠ACB∴∠ACF=∠ACB/2∵HG⊥AC∴∠CHG+∠ACF=...
∠AHE与∠CHG相等证明:∵AD平分∠BAC∴∠BAD=∠BAC/2∵BE平分∠ABC∴∠ABE=∠ABC/2∴∠AHE=∠BAD+∠ABE=(∠BAC+∠ABC)/2=(180-∠ACB)/2=90-∠ACB/2∵CF平分∠ACB∴∠ACF=∠ACB/2∵HG⊥AC∴∠CHG+∠ACF=...