解由正弦定理a/sinA=b/sinB=c/sinC=k
则a/k=sinA,b/k=sinB,c/k=sinC
代入sinC-sinB=0.5sinA
中则c/k-b/k=1/2×a/k
两边乘以k得
c-b=1a/2
即
2c-2b=a