Question

已知x=1/2,y=-2,求x（2n+1）次方·y（2n+2）次方（n为自然数）的值.

Answer 1

x^（2n+1）·y^（2n+2）

=(1/2)^(2n+1) (-2)^(2n+2)

=(2)^(-2n-1) 2^(2n+2)

=2^(-2n-1+2n+2)

=2