Question

初二方程组一道————————————————————在线等

Answer 1

x²+2xy+y²=1

(x+y)^2=1

x+y=1或-1

x+y=1,y=1-x,

2x²-y=2

2x²-1+x=2

(2x+3)(x-1)=0

x=-3/2或1

y=5/2或0

x+y=-1,y=-1-x,

2x²-y=2

2x²+1+x=2

(2x-1)(x+1)=0

x=1/2或-1

y=-1/2或0