a(1/b+1/c)+b(1/a+1/c)+c(1/a+1/b)
=a/b+a/c+b/a+b/c+c/a+c/b
=(a+b+c)/a+(a+b+c)/b+(a+b+c)/c-3
=-3
初一问题~分式若abc≠0,a+b+c=0,求：a(1/b+1/c)+b(1/a+1/c)+c(1/a+1/b)
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