因式分解:y^2-7y-(x+3)(x-4)

1个回答

  • y^2-7y-(x+3)(x-4)

    =y^2-7y+49/4-49/4-(x^2-x+1/4-1/4-12)

    =(y-7/2)^2-(x-1/2)^2-49/4+1/4+12

    =(y-7/2)^2-(x-1/2)^2

    =[(y-7/2)+(x-1/2)]×[[(y-7/2)-(x-1/2)]

    =(x+y-4)×(y-x-3)

    思路是:将y与X分别凑成完全平方的形式,然后再利用平方差公式展开整理就可得到.

    每一步骤都很详细,