∵a,b满足|a-2|+(2b+3)^2=0
∴a=2 b=-3/2
∴1/2a-2(a-3ab-1/3b^2)-3(3/2a+2ab+1/3b^2)+1
=1/2a-2a+6ab+2/3b²-9/2a-6ab-b²+1
=-6a-1/3b²+1
=-6*2-1/3*(-3/2)²+1
=-12-3/4+1
=-11又4分之3
2/1a-2(a-3ab-3/1b^2)-3(2/3a+2ab+3/1b^2)+1,其中a,b满足|a-2|+(2b+3
1个回答
相关问题
-
-(3ab-a^2)-[2a^2-(3ab-b^2)],其中a= -2,b=1
-
a3－b3＋a2b2－2ab＋b其中a＝－1，b＝2
-
5ab²-｛2a²b-3【ab²-2（2ab²+a²b】）｝,其中a,b满足|a+1|+（b-2）²=0
-
4a^2b-[3ab^2-2(3a^2b-1)],其中a=-0.1,b=1.
-
化简求值 ab^3+a^2b^3+2-2ab+3ab^3-a^2b^3+2ab-1,a=1,b=-1
-
-(-ab²+3a²b)+3(3a²b-ab²）,其中a=1/2,b=-1/3.
-
4a^2b-[3ab^2-(3a^2b-1)],其中a=-0.1,b=1.
-
(1)(-ab)^3(a^2+ab+1)+(-ab^2)^2*(-2a^2)(2)(2a+b)(2a-b)+3(2a-b
-
(1)(-ab)^3(a^2+ab+1)+(-ab^2)^2*(-2a^2)(2)(2a+b)(2a-b)+3(2a-b
-
6ab-3【3b^2-（a^2-2ab)+1] a=-2 b=-1/3