解(1)由f(x)=sin(π/3-2x)
=-sin(2x-π/3)
当2kπ-π/2≤2x-π/3≤2kπ+π/2,k属于Z时,y是减函数,
即kπ-π/12≤x≤kπ+5π/12,k属于Z时,y是减函数,
知函数的减区间为[kπ-π/12,kπ+5π/12],k属于Z.
(2)由把函数f(x)=sin(π/3-2x)的图像向右平移π/12个单位时
函数f(x)=sin(π/3-2x)
变为f(x)=sin(π/3-2(x-π/12))=sin(π/3-2x+π/6)
=sin(π/2-2x)=cos2x是偶函数,其图像关于y轴对称.
即经过图像向右平移π/12个单位时,fx的图像关于y轴对称