Question

(2+1)(2的二次方+2)(2的三次方+2)……(2的64次方)+1

Answer 1

1/（2+1）*（1/（2^2+1）*...*(1/(2^64)+1)

= 1/(2-1) * 1/（2+1）*（1/（2^2+1）*...*(1/(2^64)+1)

= 1/(2^2-1) * （1/（2^2+1）*...*(1/(2^64)+1)

= 1/(2^128-1)