题目应是 [(x-y)的四次方+6(y-x)的三次方+8(x-y)的2次方]÷2(x-y)的2次方
= [(x-y)^4-6(x-y)^3+8(x-y)^2]÷2(x-y)^2
=1/2(x-y)^2-3(x-y)+4
请采纳答案,支持我一下.