原式=-1/lnx+1/(x-1) = (1-x+lnx)/lnx(x-1)
f(2) = (1-2+ln2)/ln2 = 1-1/ln2
f(1) = lim(x->1)f(x) = -1/2
结果应该是1-1/ln2 + 1/2 = 3/2-1/ln2
我觉得是
原式=-1/lnx+1/(x-1) = (1-x+lnx)/lnx(x-1)
f(2) = (1-2+ln2)/ln2 = 1-1/ln2
f(1) = lim(x->1)f(x) = -1/2
结果应该是1-1/ln2 + 1/2 = 3/2-1/ln2
我觉得是