原式=根号下1-2sin2cos2 = 根号下(sin2)^2+(cos2)^2-2sin2cos2 =根号下(sin2-cos2)^2 =sin2-cos2 =根号2 乘以sin(2-π/4)
代数式:根号下1+2sin(π-2)cos(π+2)化简
2个回答
相关问题
-
化简根号下1-2sin(π+4)cos(π+4)
-
根号下1减sin(π+2)cos(π+2)化简是多少啊
-
化简sin(π+π/3)+2sin(x-π/3)-根号下3 *cos(2π/3-x)
-
化简:根号下 (1-sinαsinβ)^2-(cosα)^2(cosβ)^2 -π/2
-
化简1+2sin(π-2)cos(π+2)
-
(1)化简cos(π−a)sin(π2+a)sin(2π+a)cos(2π+a).
-
根号2sinπ/32*cosπ/32*cosπ/16*cosπ/18 怎么化简
-
化简根号下1+cos(3π-θ)/2 (3π/2<θ<2π)
-
函数式根号1+sin(π-2)cos(π+2)化简的结果是
-
根号2+2sin(2π-θ)-cos^2(π+θ)可化简为