Question

当x=2011时,代数式ax^5+bx^3+cx-29的值为2011;当x=-2011时,代数式ax^5+bx^3+cx

Answer 1

∵当x=2011时,代数式ax^5+bx^3+cx-29=2011

∴a2011^5+b2011^3+2011c=2040

∴当x=-2011时

ax^5+bx^3+cx-29

=a(-2011)^5+b(-2011)^3+(-2011)c-29

=-a2011^5-b2011^3-2011c-29

=-(a2011^5+b2011^3+2011c)-29

=-2040-29

=-2069