1） 1/3,1/52)倒数变换一下即可证明从该步骤得到an=1/(2n-1)3) T=(1/1*1/3+1/3*1/5+1/5*1/7+……+[1/(2n-3)][1/(2n-1)]=1/2(1-1/3+1/3-1/5+1/5-1/7+……+1/(2n-5)-1/(2n-3)+1/(2n-3)-1/(2n-1)=1/2(1-1/(2n-1) =n/(2n...
若数列{An}满足A1=1,A(n+1)=An/(2An + 1)
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