如图,抛物线y=ax2+bx+c经过A(-1,0)B(3,0)C(0,3)三点,对称轴与抛物线交于点P,与直线BC相交于

2个回答

  • 1

    A(-1,0)B(3,0)C(0,3)

    x1=-1,x2=3 x=0,y=c=3

    x1x2=c/a=-3

    a=-1

    x1+x2=2=-b/a

    b=2

    y= -x^2+2x+3

    对称轴x=-b/2a=(x1+x2)/2=1 c-b^2/4a=3-4/(-4)=4 顶点P(1,4)

    直线BC:y-3=[(3-0)/(0-3)]x

    y=-x+3

    x=1,y=2

    M(1,2) P(1,4)

    2

    过P平行BC直线

    y-4=-(x-1)

    y=5-x

    y=-x^2+2x+3

    5-x=-x^2+2x+3

    x^2-3x+2=0

    (x-2)(x-1)=0

    x=1,y=4或x=2,y=3

    Q(1,4)或Q(2,3)

    3

    |PM|=4-2=2

    |BM|^2=(3-1)^2+2^2=8

    |BM|=√8

    R(x0,y0)

    过R垂直BC直线y-y0=x-x0

    y=-x+3

    -x+3-y0=x-x0

    x=(x0+3-y0)/2

    y-y0=3-y-x0

    y=(3+y0-x0)/2

    R到BM距离d^2=[(x0+3-y0)/2-x0]^2+[(3+y0-x0)/2-y0]^2

    =2[(3-x0-y0)/2]^2

    d=√2|3-x0-y0|/2

    d*√8=2*(x0-1)

    4|3-x0-y0|/2=2(x0-1)

    |3-x0-y0|=x0-1

    a

    |3-x0-y0|=3-x0-y0时

    3-x0-y0=x0-1

    y0=-x0^2+2x0+3

    -x0^2+4x0-1=0

    (x0-2)^2=3

    x0=2-√3

    y0=7-2√3-7+4√3=2√3,3-x0-y0