Question

如图,点A,O,B在同一条直线上,角COD=90°,OE平分角AOC.OF平分角BOD,求角EOF

Answer 1

∵∠COD=90°

∴∠AOC+∠BOD=180°-∠COD=180°-90°=90°

∵OE平分∠AOC,OF平分∠BOD

∴∠EOC+∠DOF=1/2（∠AOC+∠BOD）=45°

∴∠EOF=∠COD+∠EOC+∠DOF=90°+45°=135°