1、在已知等式中,取 x = 0 ,则 (-1)^5 = f ,即 f = -1 .
2、在已知等式中,取 x = 1 ,则 (2*1-1)^5 = a+b+c+d+e+f ,所以 a+b+c+d+e+f = 1 .
设(2x-1)^5=ax^5+bx^4+cx^3+dx^2+ex+f 1.求f的值 2.
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