(3x+1)∧5=ax∧5+bx^4+cx^3+dx∧2+ex+f,求a-b+c-d+e-f的值,
1个回答
令x=-1
则-a+b-c+d-e+f=(-3+1)^5=-32
所以a-b+c-d+e-f=32
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