设1+0.23+0.34+0.65=a
原式
=(a-0.65)(a-1)-a(a-1-0.65)
=a^2-a-0.65a+0.65-a^2+a+0.65a
=0.65
（1+0.23+0.34)x(0.23+0.34+0.65)-(1+0.23+0.34+0.65)x(0.23+0.34
2个回答
相关问题
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(1+0.23+0.34)x(0.23+0.34+0.65)-(1+0.23+0.34+0.65)x(0.23+0.
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(1+0.23+0.34)×（0.23+0.34+0.65）-（1+0.23+0.34+0.65）×（0.23+0.34
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简便计算：(1+0.23+0.34)*(0.23+0.34+0.65)-(1+0.23+0.34+0.65)*(0.23
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巧算(1+0.23+0.34)*(0.23+0.34+0.65)-(1+0.23+0.34+0.65)*(0.23+0.
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(1+0.23+0.34)x(0.23+0.34+0.78)-(1+0.23+0.34+0.78)x(0.23+0.34
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（1+0.23++0.34)×（0.233+0.34+0.65）-（1+0.23+0.24+0.65）×（0.23+0.
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(1+0.23+0.34)*(0.23+0.34+0.45)-(1+0.23+0.34+0.45)*(0.23+0.34
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（1+0.23+0.34）×（0.23+0.34+0.45）-（1+0.23+0.34+0.45）×（0.23+0.34
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（1+0.23+0.34）×（0.23+0.34+0.56）-（1+0.23+0.34+0.56）×（0.23+0.34
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﹙1+0.23+0.34﹚×﹙0.23+0.34+0.56)-﹙1+0.23+0.34+0.56﹚×﹙0.23+0.34