1/3+1/15+1/35+1/63+.+1/323
=1/2(2/3+2/15+2/35+2/63+.+2/323)
=1/2[2/(1X3)+2/(3X5)+2/(5X7)+2/(7X9)+.+2/(17X19)]
=1/2[(3-1)/(1X3)+(5-3)/(3X5)+(7-5)/(5X7)+(9-7)/(7X9)+.+(19-17)/(17X19)]
=1/2[3/(1X3)-1/(1X3)+5/(3X5)-3/(3X5)+7/(5X7)-5/(5X7)+9/(7X9)-7/(7X9)+.+19/(17X19)-17/(17X19)]
=1/2（1/1-1/3+1/3-1/5+1/5-1/7+...+1/17-1/19） (1/2和1/1就这样来的)
(括号中第二项和第三项抵消,第四项和第五项抵消.）
=1/2（1-1/19）
=9/19