Question

【分解因式,后三题求过程】x²y²-16xy+64 2分之1x²+xy+2分之1y

Answer 1

x²y²-16xy+64

=(xy-8)²

2分之1x²+xy+2分之1y²

=(1/2)(x²+2xy+y²)

=(1/2)(x+y)²

4分之（x²）-xy+y²

=(1/4)(x²-4xy+4y²)

=(1/4)(x-2y)²

98-28x+2x²

=2(49-14x+x²)

=2(x-7)²

4x³+x-4x²

=x(x²-4x+1)

49-14（x-y）+（x-y）²

=(x-y-7)²