1、x³-1=(x-1)(x²+x+1)
2、(a²-b²)²-8(a²+b²)=(a+b)^2(a-b)^2-8(a^2+b^2)
=4(a-b)^2-8[4-2ab]
=4[4-4ab]-8[4-2ab]
=16-16ab-32+16ab
=16-32
=-16
1、x³-1=(x-1)(x²+x+1)
2、(a²-b²)²-8(a²+b²)=(a+b)^2(a-b)^2-8(a^2+b^2)
=4(a-b)^2-8[4-2ab]
=4[4-4ab]-8[4-2ab]
=16-16ab-32+16ab
=16-32
=-16