设P1(x1,y1),P2(x2,y2),P(x.,y.),则
(x1)²/9-(y1)²/4=1,(x2)²/9-(y2)²/4=1,
两式相减,整理得:
k2=(y1-y2)/(x1-x2)=4(x1+x2)/9(y1+y2)
=4x./9y.=4/9(k1),
∵k1∈[2,4],∴k2∈[1/9,2/9].
设P1(x1,y1),P2(x2,y2),P(x.,y.),则
(x1)²/9-(y1)²/4=1,(x2)²/9-(y2)²/4=1,
两式相减,整理得:
k2=(y1-y2)/(x1-x2)=4(x1+x2)/9(y1+y2)
=4x./9y.=4/9(k1),
∵k1∈[2,4],∴k2∈[1/9,2/9].