证明：
sint+sin(t+2/3派)+sin(t+4/3派)
=sint+sint*cos(2π/3)+cost*sin(2π/3)+sint*cos(4π/3)+cost*sin(4π/3)
=sint+sint*(-1/2)+cost*(√3/2)+sint*(-1/2)+cost*(-√3/2)
= 0
求证sint+sin(t+2/3派)+sin(t+4/3派)=0
1个回答
相关问题
-
F(X)=6SIN((派t/3+派/4)),G(X)=3*根号3COS((派T/3)+(7派/12))
-
sin（-7派\2）+tan派-2cos0+9派\4-csc7派\3=
-
已知tana=2,a属于(派,3派/2),求值(1)sin(-派/2-a) (2)sin(派+a)+2sin(3派/2+
-
(1)sin(-派/2) (2)sin(5派/4) (3)cos210度 (4)tan(19派/6)
-
高一数学填空题!sin派/6-(cos派/4)^2cos派-1/3*(tan派/6)^2-cos派+sin派/2＝?
-
cos(派/2+a)sin(3派/2-b)+sin(3派/2-a)coa(3派/2-b)=-1/2a属于(派/2,派)b
-
已知sin(派+a)=-1/2,计算：1.sin(5派-a) 2.sin(片/2+a) 3.cos(a-3派/2) 4.
-
己知sin(x+派)=-1/2计算sin(5派-x)-cos(x-3派/2)(2)sin(派/2+x)*tan(派/2+
-
已知sin(派-a)=2cos(派+a),求sin(派-a)+5cos(2派-a)/3cos(派-a)-sin(-a)
-
已知函数f(x)=2根号3sin(x/2+派/4)cos(x/2+派/4)-sin(x+派).