1+2-3-4+5+6-7-8+...+2001+2002-2003-2004=?

3个回答

  • 1+2-3-4+5+6-7-8+...+2001+2002-2003-2004

    =(1+2-3-4)+(5+67-8)+...+(2001+2002-2003-2004)

    =(-4)+(-4)+...+(-4)

    =(-4)*501

    =-2004

    1/1*3 +1/3*5 +1/5*7 +...+1/99*101

    =(1/2)(2/1*3 +2/3*5 +2/5*7 +...+2/99*101)

    =(1/2)[(1/1-1/3)+(1/3-1/5)+...+(1/99-1/101)]

    =(1/2)(1/1-1/101)

    =50/101

    (1/2005 -1)(1/2004 -1)...(1/3 -1)(1/2 -1)

    =(-2004/2005)(-2003/2004)(-2002/2003)...(-2/3)(-1/2)

    =(-1)^2004*(2004/2005)(2003/2004)...(2/3)(1/2)

    =1/2005