{3x+2y=1,①
{2x-y+z=-4 ②
{x+2y-z=3 ③
②+③得3x+y=-1 ④
①-④得y=2
把y=2代入④得3x+2=-1
x=-1
把x=-1,y=2代入②得-2-2+z=-4
z=0
所以原方程组的解是
{x=-1
{y=2
{z=0
{3x+2y=1,①
{2x-y+z=-4 ②
{x+2y-z=3 ③
②+③得3x+y=-1 ④
①-④得y=2
把y=2代入④得3x+2=-1
x=-1
把x=-1,y=2代入②得-2-2+z=-4
z=0
所以原方程组的解是
{x=-1
{y=2
{z=0