x+y+z=10 5y=20z 4x=5y
1个回答
由5y=20z;4x=5y=20z得
即x=5z,y=4z;
x+y+z=5z+4z+z=10;
所以z=1,x=5,y=4
相关问题
{5X+Y+Z①X+5Y+Z=-2②X+Y+5Z=10③
设x,y,z>0,求证:(x+y+z)^5-(x^5+y^5+z^5)>=10(x+y)(y+z)(z+x)(xy+yz
3x+7y+z=5 ,4x+10y+z=6 ,x+y+z=
(x+y+z)^5-(x+y-z)^5-(x+z-y)^5-(z+y-x)^5,
①:5×+y+z=6,②:x+5y+z=-2,③:x+y+5z=10;
x+y+2z=5 2x-y-z=4 3x+y-3z=10
{3x-2y+5z=02x+5y-10z=192x+3y+15z=13{x+y=3y+z=5x+z=6
解方程组5x+3y-z=0 5x-3y+z =-4 10x+y+z=-5 急,拜托了.
x+y+z=2 ① 2x+3y+z=38 ① x+y=3 3x-y-4z=5 ② 3x+4y+2z+56 ② y+z=5
帮忙解三元一次方程,x+y=8,x+y+z=10,x-y-z=6x+y=3,y+z=-4,z+x=5y=2x-4,3x+