Question

求极限：x趋近于无穷,定积分【0,x】（t+t^2)e^(t^2-x^2)dt的化简过程,

Answer 1

恐怕是x趋于0,这时属于0/0

用罗比达法则：

=lim(x→0)(x+x^2)e^(x^2)/[e^(x^2)2x]

=lim(x→0)(x+x^2)/(2x)

=1/2