Question

若斜率为1的直线与圆(x-1)^2(y+1)^2=2相切,则该直线的方程为

Answer 1

圆心(1,-1),半径√2

设直线方程y = x + b,x - y + b = 1

r = |1 + 1 + b|/√2 = √2

|b + 2| = 2

b = -4或b = 0