cos2x=2cos^2x-1(二倍角公式)
2cos^2x-1+3sinx+a>0
2(1-sin^2x)+3sinx+a-1>0
-2sin^2x+3sinx+a+1>0
换元:-2t^2+3t+a+1>0
a>-1-3t+2t^2
由x∈(0,π/2):
t∈(0,1)
-1-3t+2t^2
cos2x=2cos^2x-1(二倍角公式)
2cos^2x-1+3sinx+a>0
2(1-sin^2x)+3sinx+a-1>0
-2sin^2x+3sinx+a+1>0
换元:-2t^2+3t+a+1>0
a>-1-3t+2t^2
由x∈(0,π/2):
t∈(0,1)
-1-3t+2t^2