设船速度为x(x>0)时,燃料费用为Q元,则,Q=kx^3
由6=k*10^3可得k=3/500,∴Q=3/500x^3,
∴总费用Y=(3/500x^3+96).1/x=3/500x^2+96/x,
y'=6/500x-96/x^2,令y'=0得x=20,
当x∈(0.20)时,y'
设船速度为x(x>0)时,燃料费用为Q元,则,Q=kx^3
由6=k*10^3可得k=3/500,∴Q=3/500x^3,
∴总费用Y=(3/500x^3+96).1/x=3/500x^2+96/x,
y'=6/500x-96/x^2,令y'=0得x=20,
当x∈(0.20)时,y'