题目呢?
我先把你的条件列下来:
x^4+y^4=25,
x²y-xy²=-6,
求x^4-y^4+3x²y-x²y-2xy²+2y^4=?
x^4-y^4+3x²y-x²y-2xy²+2y^4
=x^4+(2y^4-y^4)+(3x²y-x²y)-2xy²
=x^4+y^4+2x²y-2xy²
=(x^4+y^4)+2(x²y-xy²)
=25+2×(-6)
=25-12
=13
有不懂的请追问.
题目呢?
我先把你的条件列下来:
x^4+y^4=25,
x²y-xy²=-6,
求x^4-y^4+3x²y-x²y-2xy²+2y^4=?
x^4-y^4+3x²y-x²y-2xy²+2y^4
=x^4+(2y^4-y^4)+(3x²y-x²y)-2xy²
=x^4+y^4+2x²y-2xy²
=(x^4+y^4)+2(x²y-xy²)
=25+2×(-6)
=25-12
=13
有不懂的请追问.