x^2-3x-1=0
x^2-3x=1
2x^3-3x^2-11x+8
=2x^3-6x^2+3x^2-11x+8
=2x(x^2-3x)+3x^2-11x+8
=2x+3x^2-11x+8
=3x^2-9x+8
=3(x^2-3x)+8
=3+8
=11
x^2-3x-1=0
x^2-3x=1
2x^3-3x^2-11x+8
=2x^3-6x^2+3x^2-11x+8
=2x(x^2-3x)+3x^2-11x+8
=2x+3x^2-11x+8
=3x^2-9x+8
=3(x^2-3x)+8
=3+8
=11