Question

解方程（2x^2-3x+1）^2+4x^2-1=6x

Answer 1

（2x^2-3x+1）^2+4x^2-1=6x

4x^2+（1-3x)^2-2乘以2x^2乘以（-3x+1)=6x

然后展开,化简得x(x^2+x-1)=0

结果为x=0,x=2分之-1+根号5,x=2分之-1-根号5